(A) To find the product of $(3x + 4)(3x - 5)$,we use the algebraic identity: $(x + a)(x + b) = x^2 + (a + b)x + ab$.Here,we let $x = 3x$,$a = 4$,and $

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(A) To find the product of $(3x + 4)(3x - 5)$,we use the algebraic identity: $(x + a)(x + b) = x^2 + (a + b)x + ab$.Here,we let $x = 3x$,$a = 4$,and $b = -5$.Substituting these values into the identity:$(3x + 4)(3x - 5) = (3x)^2 + (4 + (-5))(3x) + (4 \times (-5))$$= 9x^2 + (-1)(3x) - 20$$= 9x^2 - 3x - 20$.